Submission #31262554

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Source Code Expand

n = int(input())
a = list(map(int, input().split()))
dp = [[0] * 21 for i in range(n - 1)]
# dp[i][j] = i 番目までの符号を入れて，その計算値が j になる場合の数
dp[0][a[0]] = 1
for i in range(1, n - 1):
    for j in range(0, 21):
        if 0 <= j - a[i] <= 20:
            dp[i][j] += dp[i - 1][j - a[i]] # 直前に足し算を行った場合
        if 0 <= j + a[i] <= 20:
            dp[i][j] += dp[i - 1][j + a[i]] # 直前に引き算を行った場合
print(dp[n - 2][a[-1]])

Submission Info

Judge Result