公式
B - aaaadaa 解説 by en_translator
If you are new to learning programming and do not know where to start, please try Problem A “Welcome to AtCoder” from practice contest. There you can find a sample code for each language.
Also, if you are not familiar with problems in programming contests, we recommend you to try some problems in “AtCoder Beginners Selection” (https://atcoder.jp/contests/abs).
The string \(T\) in the following algorithm will end up in the sought string.
- Let \(T\) be an empty string.
- Inspect each character of \(S\).
- If the currently inspected character is \(x\), append \(x\) to the tail of \(x\); otherwise, append \(y\) to the end of \(T\).
Sample implementation of this algorithm in programming languages are introduced below.
n, x, y = map(str, input().split())
n = int(n)
s = input()
t = ""
for i in range(n):
if s[i] == x:
t += x
else:
t += y
print(t)
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;
char x, y;
string s;
cin >> n >> x >> y >> s;
string t = "";
for (char c : s)
{
t += c == x ? x : y;
}
cout << t << endl;
}
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