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Original proposer: vwxyz

\(H[\mathrm{cm}]\) can be converted to meters by \(\frac{H}{100}[\mathrm{m}]\). According to the definition in the problem statement, \(\mathrm{BMI}[\mathrm{kg}/\mathrm{m}^2]=\frac{10^4 \times W}{H^2}[\mathrm{kg}/\mathrm{m}^2]\).
It suffices to determine if this is greater than or equal to \(25\). This inequality is equivalent to:
\(10^4 \times W \geq 25 \times H^2\)
\(400 \times W \geq H^2\).
It suffices to implement this.

Supplement

This topic may be rather advanced for a Problem A, but using decimal types to compare \(\frac{10^4 \times W}{H^2} \geq 25\) is error-prone.
In case of this problem, the constraints guarantee that \(H\) and \(W\) is not very large, and \(25.0\) can be precisely represented with a floating-point type, so comparing \(\frac{10^4 \times W}{H^2}\) and \(25\) is highly likely to get AC, but it is safer to turn it into an integer comparison.
The test cases include one for which comparing \(\frac{W}{(\frac{H}{100})^2}\) and \(25\) will be judged WA (Wrong Answer).

Sample code in C++:

#include <bits/stdc++.h>
using namespace std;

int main(){
    int H,W;
    cin>>H>>W;
    string ans;
    if(400*W>=H*H){
        ans="Yes";
    }
    else{
        ans="No";
    }
    cout<<ans<<"\n";
}

Sample code in Python:

H,W=map(int,input().split())
if 400*W>=H*H:
    ans="Yes"
else:
    ans="No"
print(ans)