Submission #71498664

---

Source Code Expand

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define FOR(i,a,b) for(int i=(a),E##i=(b);i<=E##i;i++)
#define REV(i,a,b) for(int i=(a),E##i=(b);i>=E##i;i--)
#define CLOSE_TIE ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define psbk push_back
#define endl '\n'
template <typename T>
void _outval(string s,int p,const T &t) {cout<<s.substr(p,s.length()-p)<<'='<<t<<endl; }
template <typename T, typename... Args>
void _outval(string s,int p,const T &t,const Args &...rest){
    string n="";
    while(s[p]!=',') n+=s[p++];
    cout<<n<<'='<<t<<", ";
    _outval(s,p+1,rest...);
}
#define outval(...) _outval(#__VA_ARGS__,0,__VA_ARGS__)
#define outarr(a,be,ed)\
{cout<<(#a)<<": ";\
FOR(iiii,be,ed)cout<<'['<<iiii<<"]="<<a[iiii]<<(iiii<ed?", ":"\n");}
const int N=3e5+5;
int n,m,Q;
bool bk[N];
vector<int> e[N];
signed main(){
    CLOSE_TIE
    cin>>n>>m;
    FOR(i,1,m){
        int u,v; cin>>u>>v;
        e[v].psbk(u);
    }
    cin>>Q;
    queue<int> q;
    while(Q--){
        int op,u;
        cin>>op>>u;
        if(op==1){
            if(bk[u]) continue; bk[u]=1;
            q.push(u);
            while(!q.empty()){
                int u=q.front(); q.pop();
                for(int v:e[u])
                    if(!bk[v]){
                        bk[v]=1;
                        q.push(v);
                    }
            }
        }else cout<<(bk[u]?"Yes\n":"No\n");
    }
    return 0;
}

Submission Info

Compile Error

./Main.cpp: In function 'int main()':
./Main.cpp:39:13: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
   39 |             if(bk[u]) continue; bk[u]=1;
      |             ^~
./Main.cpp:39:33: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
   39 |             if(bk[u]) continue; bk[u]=1;
      |                                 ^~

Judge Result