Official
C - Bib Editorial by en_translator
Let \(S_i\) be the sought answer.
Person \(i\) is wearing bib \(Q_i\), so the person \(P_i\), whom person \(i\) stares at, is wearing bib \(Q_{P_i}\). Thus, we have \(S_{Q_i}=Q_{P_i}\), so the answer can be found with a for
statement like:
for i in 1..n:
S[Q[i]]= Q[P[i]]
Note that most programming languages adopts 0-based indices for arrays.
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