Submission #47534879


Source Code Expand

n, q = read_line.split.map(&.to_i)
qs = [] of Tuple(Int32, Int32, Int64)

# 非連結な頂点同士を結ぶ辺のみを抽出したグラフを作成
graph = Array.new(n) { [] of Tuple(Int32, Int64) }
uf = UnionFind.new(n)
q.times do |i|
  a, b, d = read_line.split.map(&.to_i)
  a -= 1
  b -= 1
  qs << {a, b, d.to_i64}
  if !uf.find(a, b)
    uf.union(a, b)
    graph[a] << {b, -d.to_i64}
    graph[b] << {a, d.to_i64}
  end
end

# 各連結成分でBFSしてvalidなXの値(のひとつ)を構築
x = Array.new(n, 0i64)
visited = Array.new(n, false)
n.times do |i|
  next if visited[i]
  que = [i]
  qi = 0
  visited[i] = true
  while qi < que.size
    cur = que[qi]
    qi += 1
    graph[cur].each do |adj, diff|
      if !visited[adj]
        visited[adj] = true
        x[adj] = x[cur] + diff
        que << adj
      end
    end
  end
end

# Xの値のつじつまが合っているものを出力
ans = [] of Int32
q.times do |i|
  a, b, d = qs[i]
  if x[a] - x[b] == d
    ans << i + 1
  end
end
puts ans.join(" ")

class UnionFind
  def initialize(size : Int32)
    @root = Array(Int32).new(size, -1)
  end

  def union(i, j)
    a = root(i)
    b = root(j)
    if a != b
      @root[a] += @root[b]
      @root[b] = a
    end
  end

  def find(i, j)
    root(i) == root(j)
  end

  def root(i)
    return i if @root[i] < 0
    @root[i] = root(@root[i])
  end

  def size(i)
    -@root[root(i)]
  end
end

Submission Info

Submission Time
Task F - Good Set Query
User tomerun
Language Crystal (Crystal 1.9.1)
Score 525
Code Size 1496 Byte
Status AC
Exec Time 131 ms
Memory 54444 KiB

Compile Error

I: Dependencies are satisfied
I: Building: main

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 525 / 525
Status
AC × 3
AC × 39
Set Name Test Cases
Sample example0.txt, example1.txt, example2.txt
All 000.txt, 001.txt, 002.txt, 003.txt, 004.txt, 005.txt, 006.txt, 007.txt, 008.txt, 009.txt, 010.txt, 011.txt, 012.txt, 013.txt, 014.txt, 015.txt, 016.txt, 017.txt, 018.txt, 019.txt, 020.txt, 021.txt, 022.txt, 023.txt, 024.txt, 025.txt, 026.txt, 027.txt, 028.txt, 029.txt, 030.txt, 031.txt, 032.txt, 033.txt, example0.txt, example1.txt, example2.txt, hack_001.txt, hack_002.txt
Case Name Status Exec Time Memory
000.txt AC 38 ms 18616 KiB
001.txt AC 43 ms 17864 KiB
002.txt AC 65 ms 28108 KiB
003.txt AC 57 ms 30272 KiB
004.txt AC 64 ms 25968 KiB
005.txt AC 86 ms 52628 KiB
006.txt AC 84 ms 52536 KiB
007.txt AC 82 ms 54444 KiB
008.txt AC 82 ms 52840 KiB
009.txt AC 47 ms 22204 KiB
010.txt AC 41 ms 16556 KiB
011.txt AC 44 ms 19028 KiB
012.txt AC 45 ms 20768 KiB
013.txt AC 39 ms 14104 KiB
014.txt AC 40 ms 17556 KiB
015.txt AC 46 ms 17496 KiB
016.txt AC 47 ms 19476 KiB
017.txt AC 40 ms 18816 KiB
018.txt AC 42 ms 20112 KiB
019.txt AC 47 ms 19828 KiB
020.txt AC 50 ms 19080 KiB
021.txt AC 42 ms 16972 KiB
022.txt AC 43 ms 16276 KiB
023.txt AC 50 ms 19000 KiB
024.txt AC 51 ms 15152 KiB
025.txt AC 44 ms 19524 KiB
026.txt AC 55 ms 22376 KiB
027.txt AC 60 ms 23376 KiB
028.txt AC 63 ms 26388 KiB
029.txt AC 54 ms 24132 KiB
030.txt AC 129 ms 52040 KiB
031.txt AC 131 ms 52068 KiB
032.txt AC 128 ms 51900 KiB
033.txt AC 130 ms 51952 KiB
example0.txt AC 1 ms 3240 KiB
example1.txt AC 16 ms 19524 KiB
example2.txt AC 1 ms 3352 KiB
hack_001.txt AC 1 ms 3320 KiB
hack_002.txt AC 1 ms 3248 KiB