提出 #35750498


ソースコード 拡げる

#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=(a);i<=(b);i++)
#define per(i,a,b) for(int i=(a);i>=(b);i--)
#define op(x) ((x&1)?x+1:x-1)
#define odd(x) (x&1)
#define even(x) (!odd(x))
#define lc(x) (x<<1)
#define rc(x) (lc(x)|1)
#define lowbit(x) (x&-x)
#define mp(x,y) make_pair(x,y)
typedef long long ll;
typedef unsigned long long ull;
typedef double db;
using namespace std;
const int MAXN=1e4+10,LIM=1e4,mod=998244353;
int mypow(int a,int n){
    if(!n)return 1;
    int tmp=mypow(a,n/2);tmp=1ll*tmp*tmp%mod;
    if(n&1)tmp=1ll*tmp*a%mod;return tmp;
}
int myinv(int a){return mypow(a,mod-2);}
int fact[MAXN],factinv[MAXN];
int C(int n,int m){
    if(n<m || m<0)return 0;
    return 1ll*fact[n]*factinv[m]%mod*factinv[n-m]%mod;
}
void add(int& x,int y){x=(x+y)%mod;}
void sub(int& x,int y){x=(x-y+mod)%mod;}
int P(int x){return (odd(x))?(mod-1):(1);}
//
int n,r1,r2,c1,c2,ans;
int pw[MAXN],piv[MAXN];
struct Poly{
    vector<ll>a;
    int n;
    Poly(int N=0){a.resize(N+1,0);n=N;}
    void split(int N,int mode=0){if(mode || (n>N) ){a.resize(N+1,0);n=N;}}
    void output(){rep(i,0,n)cout<<a[i]<<" ";cout<<"\n";}
};
namespace NTT{
    const int MAXN=1e5;
    ll f[MAXN],g[MAXN],h[MAXN],rev[MAXN],N;
    void change(ll* f,int N){rep(i,0,N-1)if(i<rev[i])swap(f[i],f[rev[i]]);}
    void DFT(ll* f,int N,ll rev){
        change(f,N);
        for(int len=2;len<=N;len<<=1){
            ll step=mypow(rev,(mod-1)/len);
            for(int i=0;i<N;i+=len){
                ll w=1;
                rep(j,0,len/2-1){
                    ll x=f[i+j],y=f[i+j+len/2];
                    f[i+j]=(x+w*y)%mod;
                    f[i+j+len/2]=(x-w*y%mod+mod)%mod;
                    w=1ll*w*step%mod;
                }
            }
        }
    }
    Poly ntt(Poly F,Poly G){
        int n=F.n,m=G.n;N=1;
        while(N<=(n+m))N<<=1;
        rep(i,0,N-1)f[i]=g[i]=h[i]=0;
        rep(i,0,N-1){
            rev[i]=rev[i>>1]>>1;
            if(i&1)rev[i]|=(N>>1);
        }
        rep(i,0,n)f[i]=F.a[i];
        rep(i,0,m)g[i]=G.a[i];
        DFT(f,N,3);DFT(g,N,3);
        rep(i,0,N-1)h[i]=1ll*f[i]*g[i]%mod;
        DFT(h,N,myinv(3));
        ll inv=myinv(N);
        rep(i,0,N-1)h[i]=1ll*h[i]*inv%mod;
        Poly ret(n+m);
        rep(i,0,n+m)ret.a[i]=h[i];
        return ret;
    }
};
Poly operator*(Poly p1,Poly p2){return NTT::ntt(p1,p2);}
//
int main(){
    fact[0]=1;rep(i,1,LIM)fact[i]=1ll*fact[i-1]*i%mod;
    factinv[LIM]=myinv(fact[LIM]);per(i,LIM-1,0)factinv[i]=1ll*factinv[i+1]*(i+1)%mod;
    
    pw[0]=1;rep(i,1,LIM)pw[i]=pw[i-1]*2%mod;
    piv[LIM]=myinv(pw[LIM]);per(i,LIM-1,0)piv[i]=piv[i+1]*2%mod;

    //
    cin>>n;
    rep(i,1,n){
        int r;cin>>r;
        if(r==1)r1++;else if(r==2)r2++;
    }
    rep(i,1,n){
        int c;cin>>c;
        if(c==1)c1++;else if(c==2)c2++;
    }
    if(r1+2*r2 != c1+2*c2){cout<<"0";return 0;}
    Poly F(n),G(n),H(n);
    int m=min(r2,c2);
    rep(i,0,m)F.a[i]=1ll*C(r2,i)*C(c2,i)%mod*fact[i]%mod*fact[r2-i]%mod*fact[c2-i]%mod*piv[r2+c2-2*i]%mod;
    rep(i,0,m)G.a[i]=1ll*P(i)*pw[i]%mod*factinv[i]%mod;
    rep(i,0,m)H.a[i]=1ll*fact[c1+2*(c2-i)]*factinv[r2-i]%mod*factinv[c2-i]%mod;

    F=F*G;
    rep(i,0,m)F.a[i]=1ll*F.a[i]*H.a[i]%mod,add(ans,F.a[i]);
    
    cout<<ans;

    return 0;
}

提出情報

提出日時
問題 G - Row Column Sums 2
ユーザ Crying
言語 C++ (GCC 9.2.1)
得点 600
コード長 3366 Byte
結果 AC
実行時間 13 ms
メモリ 4440 KiB

コンパイルエラー

./Main.cpp: In function ‘int mypow(int, int)’:
./Main.cpp:19:5: warning: this ‘if’ clause does not guard... [-Wmisleading-indentation]
   19 |     if(n&1)tmp=1ll*tmp*a%mod;return tmp;
      |     ^~
./Main.cpp:19:30: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the ‘if’
   19 |     if(n&1)tmp=1ll*tmp*a%mod;return tmp;
      |                              ^~~~~~

ジャッジ結果

セット名 Sample All
得点 / 配点 0 / 0 600 / 600
結果
AC × 3
AC × 37
セット名 テストケース
Sample example0.txt, example1.txt, example2.txt
All 000.txt, 001.txt, 002.txt, 003.txt, 004.txt, 005.txt, 006.txt, 007.txt, 008.txt, 009.txt, 010.txt, 011.txt, 012.txt, 013.txt, 014.txt, 015.txt, 016.txt, 017.txt, 018.txt, 019.txt, 020.txt, 021.txt, 022.txt, 023.txt, 024.txt, 025.txt, 026.txt, 027.txt, 028.txt, 029.txt, 030.txt, 031.txt, 032.txt, 033.txt, example0.txt, example1.txt, example2.txt
ケース名 結果 実行時間 メモリ
000.txt AC 8 ms 3768 KiB
001.txt AC 3 ms 3800 KiB
002.txt AC 2 ms 3580 KiB
003.txt AC 2 ms 3784 KiB
004.txt AC 2 ms 3756 KiB
005.txt AC 8 ms 4368 KiB
006.txt AC 13 ms 4244 KiB
007.txt AC 10 ms 4412 KiB
008.txt AC 5 ms 3572 KiB
009.txt AC 5 ms 3672 KiB
010.txt AC 3 ms 3704 KiB
011.txt AC 5 ms 3680 KiB
012.txt AC 5 ms 3652 KiB
013.txt AC 5 ms 3752 KiB
014.txt AC 9 ms 4404 KiB
015.txt AC 11 ms 4416 KiB
016.txt AC 11 ms 4240 KiB
017.txt AC 10 ms 4440 KiB
018.txt AC 11 ms 4440 KiB
019.txt AC 8 ms 4332 KiB
020.txt AC 8 ms 4404 KiB
021.txt AC 8 ms 4408 KiB
022.txt AC 9 ms 4408 KiB
023.txt AC 9 ms 4304 KiB
024.txt AC 11 ms 4408 KiB
025.txt AC 9 ms 4368 KiB
026.txt AC 11 ms 4412 KiB
027.txt AC 11 ms 4284 KiB
028.txt AC 11 ms 4296 KiB
029.txt AC 10 ms 4296 KiB
030.txt AC 8 ms 4296 KiB
031.txt AC 12 ms 4244 KiB
032.txt AC 8 ms 4404 KiB
033.txt AC 8 ms 4240 KiB
example0.txt AC 2 ms 3592 KiB
example1.txt AC 2 ms 3756 KiB
example2.txt AC 2 ms 3768 KiB