Contest Duration: - (local time) (100 minutes) Back to Home
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## A - Good morning Editorial by en_translator

Compare $$B$$ minutes past $$A$$ o’clock and $$D$$ minutes past $$C$$ o’clock. If $$D$$ minutes past $$C$$ o’clock is the earlier, print Aoki; otherwise, that is, if they are equal or $$B$$ minutes past $$A$$ o’clock is the earlier, then print Takahashi. With the fact taken into account that hours are significant than minutes, the following conditional branch will do.

• If $$A>C$$, print Takahashi.
• If $$A>C$$, print Aoki.
• If $$A=C$$, print Takahashi if $$B\leq D$$, and print Aoki if $$B>D$$.

Sample code in C++:

#include <bits/stdc++.h>
using namespace std;

int main(void) {
int a, b, c, d;
cin >> a >> b >> c >> d;
if (a < c)cout << "Takahashi" << endl;
else if (a > c)cout << "Aoki" << endl;
else {
if (b <= d)cout << "Takahashi" << endl;
else cout << "Aoki" << endl;
}
return 0;
}


Sample code in Python:

a,b,c,d= map(int, input().split())
if a < c:
print("Takahashi")
elif a > c:
print("Aoki")
else:
if b <= d:
print("Takahashi")
else:
print("Aoki")


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