Compare \(B\) minutes past \(A\) o’clock and \(D\) minutes past \(C\) o’clock. If \(D\) minutes past \(C\) o’clock is the earlier, print Aoki; otherwise, that is, if they are equal or \(B\) minutes past \(A\) o’clock is the earlier, then print Takahashi. With the fact taken into account that hours are significant than minutes, the following conditional branch will do.

• If \(A>C\), print Takahashi.
• If \(A>C\), print Aoki.
• If \(A=C\), print Takahashi if \(B\leq D\), and print Aoki if \(B>D\).

Sample code in C++:

#include <bits/stdc++.h>
using namespace std;

int main(void) {
	int a, b, c, d;
	cin >> a >> b >> c >> d;
	if (a < c)cout << "Takahashi" << endl;
	else if (a > c)cout << "Aoki" << endl;
	else {
		if (b <= d)cout << "Takahashi" << endl;
		else cout << "Aoki" << endl;
	}
	return 0;
}

Sample code in Python:

a,b,c,d= map(int, input().split())
if a < c: 
    print("Takahashi")
elif a > c:
	print("Aoki")
else:
    if b <= d:
        print("Takahashi")
    else:
        print("Aoki")