You can solve it by following the problem statement to calculate the inner product with arrays and loops.

Sample Code (Python)

n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))

prod = 0
for i in range(n) : prod += a[i] * b[i]
print("No" if prod else "Yes")

Sample Code (C)

#include <stdio.h>

int ri() {
	int n;
	scanf("%d", &n);
	return n;
}

int main() {
	int n = ri();
	int a[n];
	for (int i = 0; i < n; i++) a[i] = ri();
	int b[n];
	for (int i = 0; i < n; i++) b[i] = ri();
	
	int prod = 0;
	for (int i = 0; i < n; i++) prod += a[i] * b[i];
	
	puts(prod ? "No" : "Yes");
	
	return 0;
}