One can get AC by writing a conditional branch with if statement, just as the problem statement indicates.

Sample code using a conditional branch (C++)

#include<iostream>
using namespace std;

int main(){
    int x;
    cin>>x;
    if(x==0)cout<<1<<"\n";
    if(x==1)cout<<0<<"\n";
}

Also, one may use a formula which becomes \(1\) when \(x=0\) and \(0\) when \(x=1\).

Sammple code using a formula（C++）

#include<iostream>
using namespace std;

int main(){
    int x;
    cin>>x;
    cout<<1-x<<"\n";
}

Other than \(1-x\), one can also use “not \(x\)” and “\(x\) xor \(1\).”

Here, “not” denotes negation and “xor” denotes exclusive logical sum.