提出 #14361676

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ソースコード 拡げる

from heapq import heapify, heappush, heappop
import sys
input = sys.stdin.readline

def solve():
    numY = 2*10**5
    #numY = 5

    N, Q = map(int, input().split())
    PQs = [[] for _ in range(numY)]
    bels = [-1] * N
    rates = [0] * N
    for no in range(N):
        A, B = map(int, input().split())
        B -= 1
        heappush(PQs[B], (-A, no))
        bels[no] = B
        rates[no] = A

    PQMAX = []
    for y in range(numY):
        if PQs[y]:
            m, no = PQs[y][0]
            heappush(PQMAX, (-m, y, -1))

    tmUpdates = [-1] * numY
    anss = []
    for tm in range(Q):
        C, D = map(int, input().split())
        C, D = C-1, D-1
        # 転園元
        bel = bels[C]
        rate, no = PQs[bel][0]
        if no == C:
            while 1:
                heappop(PQs[bel])
                if not PQs[bel]:
                    tmUpdates[bel] = tm
                    break
                rate, no = PQs[bel][0]
                if no != C and bels[no] == bel:
                    heappush(PQMAX, (-rate, bel, tm))
                    tmUpdates[bel] = tm
                    break

        # 転園先
        if PQs[D]:
            rate0, no = PQs[D][0]
            heappush(PQs[D], (-rates[C], C))
            rate, no = PQs[D][0]
            if rate < rate0:
                heappush(PQMAX, (-rate, D, tm))
                tmUpdates[D] = tm
        else:
            rate = rates[C]
            heappush(PQs[D], (-rate, C))
            heappush(PQMAX, (rate, D, tm))
            tmUpdates[D] = tm

        # min
        rate, y, tm = PQMAX[0]
        while tm < tmUpdates[y]:
            heappop(PQMAX)
            rate, y, tm = PQMAX[0]

        anss.append(rate)

        bels[C] = D

    print('\n'.join(map(str, anss)))


solve()

提出情報

ジャッジ結果