Contest Duration: - (local time) (100 minutes) Back to Home
B - Christmas Eve Eve /

Time Limit: 2 sec / Memory Limit: 1024 MB

### 問題文

とある世界では、今日はクリスマスイブの前日です。

### 制約

• 2 \leq N \leq 10
• 100 \leq p_i \leq 10000
• p_i は偶数である。

N
p_1
p_2
:
p_N

3
4980
7980
6980

### 出力例 1

15950

7980 円の品物が半額になり、合計 4980 + 7980 / 2 + 6980 = 15950 円です。

4
4320
4320
4320
4320

### 出力例 2

15120

4 個の品物のうち 1 個だけが半額になり、合計 4320 / 2 + 4320 + 4320 + 4320 = 15120 円です。

Score : 200 points

### Problem Statement

In some other world, today is the day before Christmas Eve.

Mr. Takaha is buying N items at a department store. The regular price of the i-th item (1 \leq i \leq N) is p_i yen (the currency of Japan).

He has a discount coupon, and can buy one item with the highest price for half the regular price. The remaining N-1 items cost their regular prices. What is the total amount he will pay?

### Constraints

• 2 \leq N \leq 10
• 100 \leq p_i \leq 10000
• p_i is an even number.

### Input

Input is given from Standard Input in the following format:

N
p_1
p_2
:
p_N

### Output

Print the total amount Mr. Takaha will pay.

3
4980
7980
6980

### Sample Output 1

15950

The 7980-yen item gets the discount and the total is 4980 + 7980 / 2 + 6980 = 15950 yen.

Note that outputs such as 15950.0 will be judged as Wrong Answer.

4
4320
4320
4320
4320

### Sample Output 2

15120

Only one of the four items gets the discount and the total is 4320 / 2 + 4320 + 4320 + 4320 = 15120 yen.