提出 #73187371

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ソースコード 拡げる

#include <bits/stdc++.h>
using ll = long long int;
using namespace std;
ll read()
{
    ll k = 0,f = 1;
    char c = getchar();
    while(c < '0' || c > '9')
    {
        if(c == '-')f = -1;
        c = getchar();
    }
    while(c >= '0' && c <= '9')k = k * 10 + c - '0',c = getchar();
    return k * f; // 别忘记标记的负数要乘进去
}
// 调用时用 n=in();
void print(ll x)
{
    if(x < 0)putchar('-'),x = -x;
    if(x < 10)putchar(x + '0');
    else print(x / 10),putchar(x % 10 + '0');
}
// 直接调用 out(n) 就行了
void solve(){
    int n = read(), k = read();
    vector<int>a(n + 1);
    for(int i = 1; i <= n; i++){
        a[i] = read();
    }
    for(int i = 1; i <= n; i++){
        if(a[i] == k){
            cout << i;
            return;
        }
    }
    cout << -1;
}
signed main(){
    int T = 1;
    while(T--){
        solve();
    }
    return 0;
}

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ジャッジ結果