Submission #73134009

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Source Code Expand

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

int n, a[14][14], c[30][30];

int main() {
	scanf("%d", &n);
	for (int i = 0; i < 30; i++) c[i][0] = 1;
	for (int i = 1; i < 30; i++) {
		for (int j = 1; j <= i; j++) {
			c[i][j] = c[i - 1][j] + c[i - 1][j - 1];
		}
	}
	for (int i = 1; i < n; i++) {
		for (int j = 1; j <= n; j++) {
			a[i + 1][j] = a[i][j + 1] + c[n * 2 - i - j - 2][n - i - 1];
		}
	}
	for (int i = 1; i <= n; i++) {
		for (int j = 1; j <= n; j++) printf("%d ", a[i][j]); puts("");
	}
}

Submission Info

Compile Error

./Main.cpp: In function 'int main()':
./Main.cpp:23:17: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   23 |                 for (int j = 1; j <= n; j++) printf("%d ", a[i][j]); puts("");
      |                 ^~~
./Main.cpp:23:70: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   23 |                 for (int j = 1; j <= n; j++) printf("%d ", a[i][j]); puts("");
      |                                                                      ^~~~

Judge Result