Submission #63598856


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#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
#define rep(i,l,r) for(int i=(l);i<(r);i++)
#define all(a) begin(a),end(a)
#define sz(a) (int)(a).size()
const ll mod=998244353;
struct mint{
ll v;
mint():v(0){}
mint(ll val):v(val%mod){}
friend mint operator+(const mint&a,const mint&b){return a.v+b.v;}
friend mint operator-(const mint&a,const mint&b){return a.v-b.v;}
friend mint operator*(const mint&a,const mint&b){return a.v*b.v;}
ll val(){if(v<0)v+=mod;return v;}
};
vector<mint>power(2e6);
struct hanoi{
int size,fst;
vector<mint>ans,top;
 
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#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
#define rep(i,l,r) for(int i=(l);i<(r);i++)
#define all(a) begin(a),end(a)
#define sz(a) (int)(a).size()
const ll mod=998244353;
struct mint{
  ll v;
  mint():v(0){}
  mint(ll val):v(val%mod){}
  friend mint operator+(const mint&a,const mint&b){return a.v+b.v;}
  friend mint operator-(const mint&a,const mint&b){return a.v-b.v;}
  friend mint operator*(const mint&a,const mint&b){return a.v*b.v;}
  ll val(){if(v<0)v+=mod;return v;}
};
vector<mint>power(2e6);
struct hanoi{
  int size,fst;
  vector<mint>ans,top;
  vector<int>nec;
};
hanoi op(hanoi&a,hanoi&b){
  if(a.nec[0]==-1)return b;
  if(b.nec[0]==-1)return a;
  vector<mint>ans(3),top(3);
  vector<int>nec(3);
  rep(i,0,3){
    if(b.nec[i]==3)ans[i]=a.ans[i];
    else ans[i]=a.ans[b.nec[i]]+(power[a.size+1]-2)*b.top[i]+b.ans[i]-(b.fst==b.nec[i]?0:power[a.size]-1);
  }
  rep(i,0,3){
    if(b.nec[i]==3)top[i]=a.top[i];
    else top[i]=a.top[b.nec[i]]+b.top[i]*power[a.size]-(b.fst==b.nec[i]?0:power[a.size-1]);
  }
  rep(i,0,3){
    if(b.nec[i]==3)nec[i]=a.nec[i];
    else if(a.nec[b.nec[i]]==3)nec[i]=b.nec[i];
    else nec[i]=a.nec[b.nec[i]];
  }
  return hanoi{a.size+b.size,a.fst,ans,top,nec};
}
hanoi e(){
  return hanoi{0,0,{0,0,0},{0,0,0},{-1,-1,-1}};
}
struct segtree{
  ll n=1;
  vector<hanoi>tree;
  segtree(ll N){
    while(n<N)n*=2;
    tree.assign(2*n,e());
  }
  void set(ll i,hanoi&x){
    i+=n;
    tree[i]=x;
    while(i>1){
      i/=2;
      tree[i]=op(tree[2*i],tree[2*i+1]);
    }
  }
  hanoi prod(ll l,ll r){
    l+=n;r+=n;
    hanoi L=e(),R=e();
    while(l<r){
      if(l%2)L=op(L,tree[l]),l++;
      if(r%2)r--,R=op(tree[r],R);
      l/=2;r/=2;
    }
    return op(L,R);
  }
  hanoi get(ll i){return tree[i+n];}
};
int main(){
  cin.tie(0)->sync_with_stdio(0);
  cin.exceptions(cin.failbit);
  ll N;cin>>N;
  vector<ll>A(N);
  rep(I,0,N)cin>>A[I];
  ll a=0,b=-1e18;
  rep(I,0,N){
    ll c=a;
    a=max(a+A[I],b);
    b=c;
  }
  cout<<a<<endl;
}

Submission Info

Submission Time
Task A - Operations on a Stack
User TKTYI
Language C++ 23 (gcc 12.2)
Score 400
Code Size 2106 Byte
Status AC
Exec Time 19 ms
Memory 20304 KB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 400 / 400
Status
AC × 3
AC × 28
Set Name Test Cases
Sample example0.txt, example1.txt, example2.txt
All 000.txt, 001.txt, 002.txt, 003.txt, 004.txt, 005.txt, 006.txt, 007.txt, 008.txt, 009.txt, 010.txt, 011.txt, 012.txt, 013.txt, 014.txt, 015.txt, 016.txt, 017.txt, 018.txt, 019.txt, 020.txt, 021.txt, 022.txt, 023.txt, 024.txt, example0.txt, example1.txt, example2.txt
Case Name Status Exec Time Memory
000.txt AC 6 ms 18504 KB
001.txt AC 7 ms 18500 KB
002.txt AC 18 ms 20304 KB
003.txt AC 18 ms 20288 KB
004.txt AC 19 ms 20164 KB
005.txt AC 19 ms 20172 KB
006.txt AC 19 ms 20164 KB
007.txt AC 7 ms 18532 KB
008.txt AC 7 ms 18444 KB
009.txt AC 6 ms 18544 KB
010.txt AC 13 ms 19332 KB
011.txt AC 8 ms 18820 KB
012.txt AC 12 ms 19424 KB
013.txt AC 14 ms 19700 KB
014.txt AC 14 ms 19600 KB
015.txt AC 19 ms 20164 KB
016.txt AC 19 ms 20136 KB
017.txt AC 19 ms 20228 KB
018.txt AC 19 ms 20236 KB
019.txt AC 19 ms 20216 KB
020.txt AC 19 ms 20208 KB
021.txt AC 19 ms 20204 KB
022.txt AC 19 ms 20156 KB
023.txt AC 19 ms 20200 KB
024.txt AC 19 ms 20164 KB
example0.txt AC 7 ms 18600 KB
example1.txt AC 6 ms 18404 KB
example2.txt AC 6 ms 18492 KB


2025-03-22 (Sat)
20:49:18 +00:00