提出 #7039451

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ソースコード 拡げる

#include <bits/stdc++.h>
using namespace std;
using lint = long long int;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }
template<typename T> bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template<typename T> bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;
#define FI first
#define SE second
#define ALL(x) (x).begin(), (x).end()
#define SZ(x) ((lint)(x).size())
#define POW2(n) (1LL << (n))

struct Doubling
{
    int N, INVALID, lgD;
    vector<vector<int>> mat;
    Doubling() : N(0), lgD(0) {}
    Doubling(const vector<int> &vec_nxt, int INVALID=-1, int lgd = 0) : N(vec_nxt.size()), INVALID(INVALID), lgD(lgd)
    {
        while ((1 << lgD) < N) lgD++;
        mat.assign(lgD, vector<int>(N, INVALID));
        mat[0] = vec_nxt;
        REP(i, N) if (mat[0][i] < 0 or mat[0][i] >= N) mat[0][i] = INVALID;
        REP(d, lgD - 1) REP(i, N) if (mat[d][i] != INVALID) mat[d + 1][i] = mat[d][mat[d][i]];
    }
    int kth_next(int now, int k)
    {
        if (k >= (1 << lgD)) exit(8);
        for (int d = 0; k and now != INVALID; d++, k >>= 1) if (k & 1) now = mat[d][now];
        return now;
    }

    int distance(int l, int r) // Distance from l to [r, \infty) (Monotonic increasing)
    {
        if (l >= r) return 0;
        int ret = 0;
        IREP(d, lgD)
        {
            if (mat[d][l] < r and mat[d][l] != INVALID) ret += 1 << d, l = mat[d][l];
        }
        if (mat[0][l] == INVALID or mat[0][l] >= r) return ret + 1;
        else return -1; // Unable to reach
    }
};

int main()
{
    int N;
    cin >> N;
    vector<lint> X(N);
    cin >> X;
    lint L;
    int Q;
    cin >> L >> Q;
    vector<int> right(N);
    int r = 0;
    REP(i, N)
    {
        while (r < N - 1 and X[r + 1] <= X[i] + L) r++;
        right[i] = r;
    }

    Doubling d(right, N);
    REP(q, Q)
    {
        int a, b;
        cin >> a >> b;
        a--, b--;
        if (a > b) swap(a, b);
        cout << d.distance(a, b) << endl;
    }
}

提出情報

ジャッジ結果