提出 #44652839

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ソースコード 拡げる

#include <bits/stdc++.h>
using namespace std;

#define x first
#define y second
#define fro(i, x, y) for(int i = (x);i <= (y);i++)
#define pre(i, x, y) for(int i = (x);i >= (y);i--)

typedef long long ll;
typedef __int128 lll;
typedef unsigned int uint;
typedef pair<int, int> PII;
typedef unsigned long long ull;

const int N = 1000010;
const int mod = 998244353;

int n, m, a[N];

signed main()
{
    ios::sync_with_stdio(0), cin.tie(0);
    cin >> n >> m;
    fro(i, 1, m) cin >> a[i];
    int op[2] = {0};
    fro(i, 1, m) op[a[i] % 2]++;
    if(op[1] > 2) cout << "Impossible", exit(0);
    fro(i, 2, m - 1) if(a[i] % 2 == 1) swap(a[i], a[1]);
    fro(i, 2, m - 1) if(a[i] % 2 == 1) swap(a[i], a[m]);
    fro(i, 1, m) cout << a[i] << " "; cout << "\n";
    if(m == 1)
    {
        if(a[1] == 1) cout << "1\n1";
        else cout << "2\n" << a[1] - 1 << " 1";
    }
    else
    {
        vector<int> ans; ans.clear();
        if(a[1] != 1) ans.push_back(a[1] - 1);
        fro(i, 2, m - 1) ans.push_back(a[i]);
        ans.push_back(a[m] + 1);
        cout << ans.size() << "\n";
        for(auto i : ans) cout << i << " ";
    }
    return 0;
}

提出情報

コンパイルエラー

./Main.cpp: In function ‘int main()’:
./Main.cpp:6:22: warning: this ‘for’ clause does not guard... [-Wmisleading-indentation]
    6 | #define fro(i, x, y) for(int i = (x);i <= (y);i++)
      |                      ^~~
./Main.cpp:30:5: note: in expansion of macro ‘fro’
   30 |     fro(i, 1, m) cout << a[i] << " "; cout << "\n";
      |     ^~~
./Main.cpp:30:39: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the ‘for’
   30 |     fro(i, 1, m) cout << a[i] << " "; cout << "\n";
      |                                       ^~~~

ジャッジ結果