If you have no idea, start with Problem A - Welcome to AtCoder in practice contest, where you can find basic input/output sample code. We also recommend AtCoder Beginners Selection.

---

To solve this problem, the following four operations are required:

1. Receive \(A\) and \(D\).
2. Compare \(A\) and \(B\).
3. Branch the program depending on the result of comparison.
4. Print the string Yes or No.

---

1. Input

We can reuse the sample code in Welcome to AtCoder. For example, if you use Python, the page contains the following code as “Example of Python”:

# -*- coding: utf-8 -*-
# get a integer
a = int(raw_input())
# get two integers separated with half-width break
b, c = map(int, raw_input().split())
# get a string
s = raw_input()
# output
print str(a+b+c) + " " + s

We can use line 5 as follows:

A, D = map(int, input().split())

2. Comparison

Most languages have <= operator. “\(A\) is less than or equal to \(D\)” can be written as A <= D.

3. Conditional branch

Most languages have an if statement or a conditional operator (ternary operator); use either of them with 2. The actual syntax varies depending on your language; use your favorite search engine with “[language] if” (replace “[replace]” with your language).

4. Output

Again, we can reuse the code from Welcome to AtCoder. For example, in case of Python, we can use line 9: replace "{} {}".format(a+b+c, s) with "Yes" and you can print Yes. Same should apply to most of the other languages too. (In AtCoder, the output checker is case-sensitive by default.)

---

We present two samples for each of Python and C++.

(Python: if statement)

A, D = map(int, input().split())
if A <= D:
    print("Yes")
else:
    print("No")

（Python: conditional operator）

A, D = map(int, input().split())
print("Yes" if A <= D else "No")

（C++: if statement）

#include <iostream>
using namespace std;
int main() {
    int A, D;
    cin >> A >> D;
    if (A <= D) {
        cout << "Yes" << endl;
    } else {
        cout << "No" << endl;
    }
}

（C++: conditional operator）

#include <iostream>
using namespace std;
int main() {
    int A, D;
    cin >> A >> D;
    cout << (A <= D ? "Yes" : "No") << endl;
}