提出 #73328592

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ソースコード 拡げる

#include <bits/stdc++.h>
using namespace std;

using ll = long long;
template <typename T>
using vc = vector<T>;
template <typename T>
using vv = vc<vc<T>>;
using vll = vector<ll>;
using vvll = vector<vector<ll>>;

#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)
#define all(v) (v).begin(), (v).end()
#define vc_unique(v) v.erase(unique(v.begin(), v.end()), v.end()) // 重複削除(ソート後限定)
#define next_p(v) next_permutation(v.begin(), v.end())            // 辞書順の次(ソート後限定)
#define keta(n) cout << fixed << setprecision(n)                  // 小数点以下の桁数指定

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    ll n;
    cin >> n;
    vvll G(329, vll(n, 0));
    rep(i, n) cin >> G.at(0).at(i), G.at(0).at(i)--;

    string e100 = "00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001110100111110011110000101000101011101010100001010111";

    rep(i, 328)
    {
        rep(j, n)
        {
            G.at(i + 1).at(j) = G.at(i).at(G.at(i).at(j));
        }
    }


    vll ans(n, 0);

    rep(i, n)
    {
        ans.at(i) = i;
    }

    rep(i, n)
    {
        rep(j, 329)
        {
            if (e100.at(j) == '1')
            {
                ans.at(i) = G.at(j).at(ans.at(i));
            }
        }
    }

    rep(i, n)
    {
        cout << ans.at(i) << " ";
    }
    cout << "\n";

    return 0;
}

提出情報

ジャッジ結果