This problem asks to rearrange elements in a sequence in specific order. This operation is called sort, which is provided as a standard feature in most languages. For example, Python and C++ both provides a function named sort.

To solve the problem, concatenate \(A\) and \(B\) to define \(C\), sort \(C\), inspect the elements of \(C\), and check if adjacent elements are both contained in \(A\).

To determine if a value is contained in a sequence, it is useful to use the in operator in Python, and set operator in C++, for example.

Sample code (Python)

N, M = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
C = A + B
C.sort()
for i in range(N + M - 1):
    if C[i] in A and C[i + 1] in A:
        print("Yes")
        exit()
print("No")

Sample code (C++)

#include <bits/stdc++.h>
using namespace std;

int main() {
    int N, M;
    cin >> N >> M;
    vector<int> A(N), B(M);
    for (auto& x : A) cin >> x;
    for (auto& x : B) cin >> x;

    auto C = A;
    for (auto x : B) C.push_back(x);
    sort(C.begin(), C.end());

    set<int> st(A.begin(), A.end());

    for (int i = 0; i < N + M - 1; ++i) {
        if (st.contains(C[i]) && st.contains(C[i + 1])) {
            cout << "Yes" << endl;
            return 0;
        }
    }
    cout << "No" << endl;
}