This problem can be solved by using a lop to read the scores and checking if each of them is \(L\) or greater.

Sample code (Python):

n,l = map(int,input().split())
a = list(map(int,input().split()))
ok = 0

for x in a:
    if x >= l:
        ok += 1

print(ok)

Sample code (C++):

#include<bits/stdc++.h>

using namespace std;

int main(){
  int n,l;
  cin >> n >> l;
  int ok=0;
  for(int i=0;i<n;i++){
    int a;
    cin >> a;
    if(a>=l){ok++;}
  }
  cout << ok << "\n";
  return 0;
}