Official
A - Edge Checker Editorial by en_translator
The points numbered \(a\) and \(b\) are directly connected with a line segment if and only if \(b-a = 1\) or \(b-a = 9\).
Therefore, we can make the following program to get accepted for this problem.
- First, read \(a\) and \(b\) from the Standard Input.
- Next, check if \(b-a = 1\) or \(b-a=9\) holds.
- If it holds, output
Yes
to the Standard Output. - If it doesn’t, output
No
to the Standard Output.
- If it holds, output
Inputting and outputting can be achieved in different ways in different languages, so check the specification of the language you use.
In order to “check if \(b-a = 1\) or \(b-a=9\) holds,” you can use the conditional branch (like if statement), which is a standard feature of programming languages.
The following is a sample code in C++.
#include <iostream>
using namespace std;
int main(void)
{
int a, b;
cin >> a >> b;
if(b-a == 1 || b-a == 9) cout << "Yes" << endl;
else cout << "No" << endl;
return 0;
}
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