Official
A - Exact Price Editorial by en_translator
It is possible if and only if \(X\) is not zero and \(X\) is divisible by \(100\).
Sample code (C++)
#include <bits/stdc++.h>
using namespace std;
int main(){
int x; cin >> x;
if(x == 0 || x % 100 != 0) cout << "No" << endl;
else cout << "Yes" << endl;
}
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