Submission #4556340


Source Code Expand

#include <bits/stdc++.h>
using namespace std;

using VS = vector<string>;    using LL = long long;
using VI = vector<int>;       using VVI = vector<VI>;
using PII = pair<int, int>;   using PLL = pair<LL, LL>;
using VL = vector<LL>;        using VVL = vector<VL>;

#define ALL(a)  begin((a)),end((a))
#define RALL(a) (a).rbegin(), (a).rend()
#define SZ(a) int((a).size())
#define SORT(c) sort(ALL((c)))
#define RSORT(c) sort(RALL((c)))
#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))
#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)
#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)
//#pragma GCC optimize ("-O3") 
#ifdef YANG33
#include "mydebug.hpp"
#else
#define DD(x) 
#endif
const int INF = 1e9;                          const LL LINF = 1e16;
const LL MOD = 1000000007;                    const double PI = acos(-1.0);
int DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 };    int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };

/* -----  2019/03/12  Problem: ABC 083 D / Link: http://abc083.contest.atcoder.jp/tasks/abc083_d  ----- */

struct Cumusum {
	vector<LL>csum;
	Cumusum(vector<LL>&a) {
		csum.assign((int)a.size() + 1, 0);
		for (int i = 0; i < (int)a.size(); i++) {
			csum[i + 1] = csum[i] + a[i];
		}
	}
	LL query(int l, int r) {
		return csum[r] - csum[l];
	}
};

int main() {
	cin.tie(0);
	ios_base::sync_with_stdio(false);

	string s; cin >> s;
	VL z(SZ(s));
	FOR(i, 0, SZ(s)) {
		z[i] = s[i] == '0';
	}
	Cumusum zeros(z);

	LL ans = (SZ(s) + 1) / 2;

	int L = SZ(s) / 2 - 1;
	int R = (SZ(s) & 1 ? SZ(s) / 2 + 1 : SZ(s) / 2);
	while (10) {
		if (L < 0 || R >= SZ(s))break;
		int W = R - L + 1;
		LL sum = zeros.query(L, R + 1);
		if (W == sum || !sum) {
			// ok
			ans = max(ans, (LL)SZ(s) - L);
		}
		else break;

		L--, R++;
	}

	cout << (ans) << "\n";

	return 0;
}

Submission Info

Submission Time
Task D - Wide Flip
User Yang33
Language C++14 (GCC 5.4.1)
Score 500
Code Size 1867 Byte
Status AC
Exec Time 3 ms
Memory 2000 KiB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 500 / 500
Status
AC × 3
AC × 30
Set Name Test Cases
Sample s1.txt, s2.txt, s3.txt
All 01.txt, 02.txt, 03.txt, 04.txt, 05.txt, 06.txt, 07.txt, 08.txt, 09.txt, 10.txt, 11.txt, 12.txt, 13.txt, 14.txt, 15.txt, 16.txt, 17.txt, 18.txt, 19.txt, 20.txt, 21.txt, 22.txt, 23.txt, 24.txt, 25.txt, 26.txt, 27.txt, s1.txt, s2.txt, s3.txt
Case Name Status Exec Time Memory
01.txt AC 3 ms 2000 KiB
02.txt AC 3 ms 2000 KiB
03.txt AC 3 ms 2000 KiB
04.txt AC 3 ms 2000 KiB
05.txt AC 3 ms 2000 KiB
06.txt AC 3 ms 2000 KiB
07.txt AC 3 ms 2000 KiB
08.txt AC 3 ms 2000 KiB
09.txt AC 3 ms 2000 KiB
10.txt AC 3 ms 2000 KiB
11.txt AC 3 ms 2000 KiB
12.txt AC 3 ms 2000 KiB
13.txt AC 3 ms 2000 KiB
14.txt AC 3 ms 2000 KiB
15.txt AC 3 ms 2000 KiB
16.txt AC 3 ms 2000 KiB
17.txt AC 3 ms 2000 KiB
18.txt AC 3 ms 2000 KiB
19.txt AC 3 ms 2000 KiB
20.txt AC 3 ms 2000 KiB
21.txt AC 1 ms 256 KiB
22.txt AC 1 ms 256 KiB
23.txt AC 1 ms 256 KiB
24.txt AC 1 ms 256 KiB
25.txt AC 1 ms 256 KiB
26.txt AC 1 ms 256 KiB
27.txt AC 1 ms 256 KiB
s1.txt AC 1 ms 256 KiB
s2.txt AC 1 ms 256 KiB
s3.txt AC 1 ms 256 KiB