Problem Statement

Keyence has N bases worldwide, numbered 1 to N. Base i has W_i employees, and at 0 o'clock in Coordinated Universal Time (UTC), it is X_i o'clock at base i.

You want to hold a one-hour meeting across the entire company. Each employee can only participate in the meeting if the meeting time is completely within the 9:00-18:00 time slot at their base. Find the maximum number of employees who can participate when deciding the meeting time to allow as many employees as possible to participate.

Constraints

• 1\leq N \leq 1000
• 1\leq W_i \leq 10^6
• 0\leq X_i < 24
• All input values are integers.

Sample Input 1

3
5 0
3 3
2 18

Sample Output 1

8

Consider holding the meeting from 14:00 to 15:00 in UTC.

• The meeting is held from 14:00 to 15:00 at base 1, so the 5 employees at base 1 can participate in the meeting.
• The meeting is held from 17:00 to 18:00 at base 2, so the 3 employees at base 2 can participate in the meeting.
• The meeting is held from 8:00 to 9:00 at base 3, so the 2 employees at base 3 cannot participate in the meeting.

Thus, a total of 5+3=8 employees can participate in the meeting. No meeting time allows more employees to participate.

Sample Input 2

2
1 10
1000000 20

Sample Output 2

1000000

Sample Input 3

6
31 3
20 8
11 5
4 3
47 14
1 18

Sample Output 3

67

Problem Statement

You are given an integer sequence of length N, A=(A_1,A_2,\ldots,A_N), and an integer M.

Determine whether it is possible to remove one of the N elements of A so that the sum of the remaining (N-1) elements is exactly M.

Constraints

• 2\le N\le 100
• 0\le M\le 10000
• 0\le A_i\le 100
• All input values are integers.

Sample Input 1

4 10
3 2 3 4

Sample Output 1

Yes

If you choose A_1,A_3,A_4, the sum is 3+3+4=10. Therefore, print Yes.

Sample Input 2

5 16
3 3 4 2 5

Sample Output 2

No

No matter how you choose four elements, their sum is not equal to 16. Therefore, print No.

Sample Input 3

6 16
0 8 0 2 6 8

Sample Output 3

Yes

Problem Statement

We have N cups of ice cream.
The flavor and deliciousness of the i-th cup are F_i and S_i, respectively (S_i is an even number).

You will choose and eat two of the N cups.
Your satisfaction here is defined as follows.

• Let s and t (s \ge t) be the deliciousness of the eaten cups.
  • If the two cups have different flavors, your satisfaction is \displaystyle s+t.
  • Otherwise, your satisfaction is \displaystyle s + \frac{t}{2}.

Find the maximum achievable satisfaction.

Constraints

• All input values are integers.
• 2 \le N \le 3 \times 10^5
• 1 \le F_i \le N
• 2 \le S_i \le 10^9
• S_i is even.

Sample Input 1

4
1 4
2 10
2 8
3 6

Sample Output 1

16

Consider eating the second and fourth cups.

• The second cup has a flavor of 2 and deliciousness of 10.
• The fourth cup has a flavor of 3 and deliciousness of 6.
• Since they have different flavors, your satisfaction is 10+6=16.

Thus, you can achieve the satisfaction of 16.
You cannot achieve a satisfaction greater than 16.

Sample Input 2

4
4 10
3 2
2 4
4 12

Sample Output 2

17

Consider eating the first and fourth cups.

• The first cup has a flavor of 4 and deliciousness of 10.
• The fourth cup has a flavor of 4 and deliciousness of 12.
• Since they have the same flavor, your satisfaction is 12+\frac{10}{2}=17.

Thus, you can achieve the satisfaction of 17.
You cannot achieve a satisfaction greater than 17.

Problem Statement

There is a directed graph with N vertices and N edges.
The i-th edge goes from vertex i to vertex A_i. (The constraints guarantee that i \neq A_i.)
Find a directed cycle without the same vertex appearing multiple times.
It can be shown that a solution exists under the constraints of this problem.

Notes

The sequence of vertices B = (B_1, B_2, \dots, B_M) is called a directed cycle when all of the following conditions are satisfied:

• M \geq 2
• The edge from vertex B_i to vertex B_{i+1} exists. (1 \leq i \leq M-1)
• The edge from vertex B_M to vertex B_1 exists.
• If i \neq j, then B_i \neq B_j.

Constraints

• All input values are integers.
• 2 \le N \le 2 \times 10^5
• 1 \le A_i \le N
• A_i \neq i

Sample Input 1

7
6 7 2 1 3 4 5

Sample Output 1

4
7 5 3 2

7 \rightarrow 5 \rightarrow 3 \rightarrow 2 \rightarrow 7 is indeed a directed cycle.

Here is the graph corresponding to this input:

Here are other acceptable outputs:

4
2 7 5 3

3
4 1 6

Note that the graph may not be connected.

Sample Input 2

2
2 1

Sample Output 2

2
1 2

This case contains both of the edges 1 \rightarrow 2 and 2 \rightarrow 1.
In this case, 1 \rightarrow 2 \rightarrow 1 is indeed a directed cycle.

Here is the graph corresponding to this input, where 1 \leftrightarrow 2 represents the existence of both 1 \rightarrow 2 and 2 \rightarrow 1:

Sample Input 3

8
3 7 4 7 3 3 8 2

Sample Output 3

3
2 7 8

Here is the graph corresponding to this input:

Problem Statement

You are given a sequence of positive integers A=(a_1,\ldots,a_N) of length N.
There are (2^N-1) ways to choose one or more terms of A. How many of them have an integer-valued average? Find the count modulo 998244353.

Constraints

• 1 \leq N \leq 100
• 1 \leq a_i \leq 10^9
• All values in input are integers.

Sample Input 1

3
2 6 2

Sample Output 1

6

For each way to choose terms of A, the average is obtained as follows:

• If just a_1 is chosen, the average is \frac{a_1}{1}=\frac{2}{1} = 2, which is an integer.

• If just a_2 is chosen, the average is \frac{a_2}{1}=\frac{6}{1} = 6, which is an integer.

• If just a_3 is chosen, the average is \frac{a_3}{1}=\frac{2}{1} = 2, which is an integer.

• If a_1 and a_2 are chosen, the average is \frac{a_1+a_2}{2}=\frac{2+6}{2} = 4, which is an integer.

• If a_1 and a_3 are chosen, the average is \frac{a_1+a_3}{2}=\frac{2+2}{2} = 2, which is an integer.

• If a_2 and a_3 are chosen, the average is \frac{a_2+a_3}{2}=\frac{6+2}{2} = 4, which is an integer.

• If a_1, a_2, and a_3 are chosen, the average is \frac{a_1+a_2+a_3}{3}=\frac{2+6+2}{3} = \frac{10}{3}, which is not an integer.

Therefore, 6 ways satisfy the condition.

Sample Input 2

5
5 5 5 5 5

Sample Output 2

31

Regardless of the choice of one or more terms of A, the average equals 5.