Problem Statement

You are given an integer N at least 100. Print the last two digits of N.

Strictly speaking, print the tens and ones digits of N in this order.

Constraints

• 100 \le N \le 999
• N is an integer.

Sample Input 1

254

Sample Output 1

54

The last two digits of 254 are 54, which should be printed.

Sample Input 2

101

Sample Output 2

01

The last two digits of 101 are 01, which should be printed.

Problem Statement

There is an enemy with stamina A. Every time you attack the enemy, its stamina reduces by B.

At least how many times do you need to attack the enemy to make its stamina 0 or less?

Constraints

• 1 \le A,B \le 10^{18}
• A and B are integers.

Sample Input 1

7 3

Sample Output 1

3

Attacking three times make the enemy's stamina -2.

Attacking only twice makes the stamina 1, so you need to attack it three times.

Sample Input 2

123456789123456789 987654321

Sample Output 2

124999999

Sample Input 3

999999999999999998 2

Sample Output 3

499999999999999999

Problem Statement

There were N contestants in the qualification round of a programming contest. All contestants got distinct ranks.
You are given a length-N string S, which represents whether the contestants want to participate in the final round or not. Specifically,

• if the i-th character of S is o, the contestant ranked i-th in the qualification wants to participate in the final;
• if the i-th character of S is x, the contestant ranked i-th in the qualification does not want to participate in the final.

Among those who want to participate in the final, K contestants with the smallest ranks advance to the final.

Print a string T of length N that satisfies the following conditions:

• if the contestant ranked i-th in the qualification advances to the final, the i-th character of T is o;
• if the contestant ranked i-th in the qualification does not advance to the final, the i-th character of T is x.

Constraints

• N and K are integers.
• 1 \le K \le N \le 100
• S is a string of length N consisting of o and x.
• S has at least K o's.

Sample Input 1

10 3
oxxoxooxox

Sample Output 1

oxxoxoxxxx

In this input, N=10 people took part in the qualification round, and K=3 of them advance to the final.

• The participant who ranked 1-st in the qualification wants to participate in the final, so the participant advances to the final. 1 participant has advanced so far.
• The participants who ranked 2-nd and 3-rd in the qualification do not want to participate in the final, so the participants do not advance to the final.
• The participant who ranked 4-th in the qualification wants to participate in the final, so the participant advances to the final. 2 participants have advanced so far.
• The participants who ranked 5-th in the qualification does not want to participate in the final, so the participant does not advance to the final.
• The participant who ranked 6-th in the qualification wants to participate in the final, so the participant advances to the final. 3 participants have advanced so far.
• Now that 3 people have advanced to the final, no participants ranked 7-th or lower advance to the final.

Problem Statement

Takahashi has a string S consisting of lowercase English letters.

On this string, he will do the operation below just once.

• First, choose a non-negative integer K.
• Then, shift each character of S to the right by K (see below).

Here,

• a shifted to the right by 1 is b;
• b shifted to the right by 1 is c;
• c shifted to the right by 1 is d;
• \cdots
• y shifted to the right by 1 is z;
• z shifted to the right by 1 is a.

For example, b shifted to the right by 4 is f, and y shifted to the right by 3 is b.

You are given a string T. Determine whether Takahashi can make S equal T by the operation above.

Constraints

• Each of S and T is a string of length between 1 and 10^5 (inclusive) consisting of lowercase English letters.
• The lengths of S and T are equal.

Sample Input 1

abc
ijk

Sample Output 1

Yes

When Takahashi chooses K=8,

• a is shifted to the right by 8 and becomes i,
• b is shifted to the right by 8 and becomes j,
• c is shifted to the right by 8 and becomes k,

and now S and T are equal.
Therefore, he can make S equal T, so Yes should be printed.

Sample Input 2

z
a

Sample Output 2

Yes

Choosing K=1 makes S and T equal.
Note that the letter on the right of z is a.

Sample Input 3

ppq
qqp

Sample Output 3

No

There is no non-negative integer K that he can choose to make S equal T, so No should be printed.

Sample Input 4

atcoder
atcoder

Sample Output 4

Yes

Choosing K=0 makes S and T equal.

Problem Statement

You are given a string S of length N consisting of lowercase English letters. Each character of S is painted in one of the M colors: color 1, color 2, ..., color M; for each i = 1, 2, \ldots, N, the i-th character of S is painted in color C_i.

For each i = 1, 2, \ldots, M in this order, let us perform the following operation.

• Perform a right circular shift by 1 on the part of S painted in color i. That is, if the p_1-th, p_2-th, p_3-th, \ldots, p_k-th characters are painted in color i from left to right, then simultaneously replace the p_1-th, p_2-th, p_3-th, \ldots, p_k-th characters of S with the p_k-th, p_1-th, p_2-th, \ldots, p_{k-1}-th characters of S, respectively.

Print the final S after the above operations.

The constraints guarantee that at least one character of S is painted in each of the M colors.

Constraints

• 1 \leq M \leq N \leq 2 \times 10^5
• 1 \leq C_i \leq M
• N, M, and C_i are all integers.
• S is a string of length N consisting of lowercase English letters.
• For each integer 1 \leq i \leq M, there is an integer 1 \leq j \leq N such that C_j = i.

Sample Input 1

8 3
apzbqrcs
1 2 3 1 2 2 1 2

Sample Output 1

cszapqbr

Initially, S = apzbqrcs.

• For i = 1, perform a right circular shift by 1 on the part of S formed by the 1-st, 4-th, 7-th characters, resulting in S = cpzaqrbs.
• For i = 2, perform a right circular shift by 1 on the part of S formed by the 2-nd, 5-th, 6-th, 8-th characters, resulting in S = cszapqbr.
• For i = 3, perform a right circular shift by 1 on the part of S formed by the 3-rd character, resulting in S = cszapqbr (here, S is not changed).

Thus, you should print cszapqbr, the final S.

Sample Input 2

2 1
aa
1 1

Sample Output 2

aa