In this problem, you need to check for each of the \(N\) words if it coincides with one of the five words.
One can write five if statements in a for statement, but there are a little simpler way: store the elements that are different in a if statement into an array and use a for statement instead.”
Specifically, construct the following array: word = {"and", "not", "that", "the", "you"}, then the for loop for \(i=0,1,2,3,4\) should contain an if statement like if(W_i == word[i]){result = true;}.
See also the sample code.

Sample code (C++):

#include<bits/stdc++.h>

using namespace std;

vector<string> word={"and", "not", "that", "the", "you"};

int main(){
  int n;
  cin >> n;
  bool res=false;
  for(int i=0;i<n;i++){
    string s;
    cin >> s;
    for(auto &nx : word){
      if(s==nx){res=true;}
    }
  }
  if(res){cout << "Yes\n";}else{cout << "No\n";}
  return 0;
}